Question

Assume that a simple random sample has been selected and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Listed below are brain volumes in cm of unrelated subjects used in a study. Use a 0.05 significance level to test the claim that the population of brain volumes has a mean equal to 1099.4 cm. 964 1026 1272 1078 1071 1173 1067 1348 1101 1203 VIAL are me hypoteses O A. Ho: u = 1099.4 cm Hy: 12 1099.4 cm OB. Ho: p= 1099.4 cm H:!<1099.4 cm Hop# 1099.4 cm H = 1099.4 cm C. He: p= 1099.4 cm H: #1099.4 cm3 Identify the test statistic ta (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. parts Clear All 2 remaining Check Answer

Answer 1

1)

Test statistics is = (sample mean - claimed mean)/(s.d/√n)

So first we need to find the sample mean and s.d of the given data

Sample mean = 1130.3

S.d = 117.4886

N = 10

Claimed mean = 1099.4

After substitution

Test statistics t = 0.83169243398 ~ 0.832

2)

It is itself given in the question

Z = -1

But calculation is

Test statistics z = (oberved p - claimed p)/standard error

Standard error = √{claimed p*(1-claimed p)/√n

Observed P = 66/144

N = 144

Claimed P = 0.5

After substitution

Test statistics z = -1