Question

The choices for the bottom statement are "stays the same," "inceases," or "decreases."

Consider light of a certain wavelength (a) being diffracted by a grating with a certain spacing (d). Use the given equation with m = 1 to complete the table, then fill in the statement that follows. mi = dsin (0) Wavelength of light (nm) Spacing of grating (um) Angle of diffraction (degrees) 495 1.00 495 2.00 639 1.00 The angle of diffraction with larger spacing, and it with longer wavelength.

Answer 1

mx = dsm (0) Here, m=1 1=d sm10). 10 = similar where, x= ware length do spaning of grating. x = 495mm = 495810-9m d = 1.00um = 1x10-6 m 1:2=sml ( 495 po t.2967° . <

x = 495 mm - 495x10 d = 2 um = 2x 10-bm. o =smt 495x109 m) 2x10675) = 14-33 ° CI) - 639 nm - 639x109 m. d=1 um = 1x10-6 m. o = sant (639x10-9 ( 1x10-6 m) = 39.720 Here, o represent angle of diffraction. I from the above three calculations it is observed that, The angle of diffraction (0) decreases with larger spacing (from f), and it increash with unger wavelength. (from fW).