Question

3. A ssume the FET in tke cicuit below hud VERO.SSV and Kz 16 mA/V2 AVDD V a s5uming 20, choose valuas fa R R 2 and Rs that I mA V oVD 2.4v IRa oVs Ran Va 2.0Vand Irg spA. change b By prozimately what percent nge wouled T in Ca)if O.02 ) Assemeng the Fe T parematass and the perating point for the FET. in b evaluati Fu and lo are

Answer 1

Giveno that- RD mA/v2 VG = 2V mA,Vp-2-uv Given Ipこ o.5 RG SMA RSD hmsa 5-VD oRD put valuuES 5-2.U: 0-5RD 2-620-5RD RDTS.21R -IRGCRGRRC2)20 ut value 5-5x63 CRantaRG2)ニ5 BGI+ RG2 100 Va RGYRG2 2ニ put Raa value Raity0=1000 => |RaiにG6ok

that e RmDO こaエ ニ16 CVas-くt)と 2 (vas-vt)= Vas-Vt \/4 6.25+Vヒニ 0.25+0-55 VaS VGS 0-8 VG-VS= 0-の8 2 VS0 8 Vs 12V om&dauo VS-D=エORS RS2-41KR 1,2ニ 0-SRS ニ leody ffect n s givem ley Fo K VCS-V£ 2Vns 2 RG2IRG -Vas RS O put valucs VGs-Ip C2-42D 2- 1p 2- VasS 2-2-47O

enter 1くVしー 5- IpRp-Vps-Rsエp-0 Leut value, S-s.2ID~Vos-2-4エDニb 5-3-67D fut values- 055)(1 1+ 0-62(5- 2-2.4In- 8 C1-45-2.4 In 1+o -1- oI52I0 エo= 8(2-1025+5-96Fp?--6-A6Zo)C1.1-0-152エn) Iロニ8(2-31275-0-3135810+6-336エD-0.835g210) C 2 -3-650H0 0S732ID Tos 8€231235-8-8SHE+-33332-チ- Ip= 8(2-31275-コ.9コs Ho +コ-333エ0-0.875521D 2-31255-ヨ-395エntヨ3937p-0.87552エpこ6-125エD 0.89552 エp'-9-393エn2488-1エロ -2-3129S20 To3-8.uuuIp 9 251 2-641S0 nsoivim Ioこ0-5o123 cleage TN (2 S0129-6-SoD D S 258o K(Vas-veaAvos) at エp=b-50123m A Nasz 2-4 (0-Sot23) -a969 V Vo8ニ NIDCCOTS61 23) -19 V

IG (o-a369-0-55 t 6-62x1-13) 1Go.2469Y0238 4.b44ummAIN D 243 25 K2 4.0444 Yo 2u3- 252 OY