Homework Answers
Molar mass of H2 = 2.016 g/mol
mass of H2 = 5*10^3 g
mol of H2 = (mass)/(molar mass)
= 5*10^3/2.016
= 2.48*10^3 mol
According to balanced equation
mol of CH3OH formed = (1/2)* moles of H2
= (1/2)*2.48*10^3
= 1.24*10^3 mol
Molar mass of CH3OH,
MM = 1*MM(C) + 4*MM(H) + 1*MM(O)
= 1*12.01 + 4*1.008 + 1*16.0
= 32.042 g/mol
mass of CH3OH = number of mol * molar mass
= 1.24*10^3*32.04
= 3.973*10^4 g
% yield = actual mass*100/theoretical mass
= 3.5*10^4*100/3.973*10^4
= 88.1 %
Answer: 88.1 %
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