Question

Question 3 of 15 Determine the number of atoms of O in 92.3 moles of Cr3(PO4)2. atoms 1 2 3 х 5 6 7 8 9 +/- X 100

Answer 1

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Imole of C&z (Oyla produce of moles of o in Imole of o, there are 6.023 X 10 23 atoms of o Avogadro's number Imole of Cr3(PO4)2 produce 8X 6.023 x 1023 atoms of o 92.3 moles of Coz (PO4)2 produce atoms of = 8x6.023 810 23 x 9213 mol Imol = 4:45 8 10 26 atoms of o Hence, the number of O atoms in 92.3 moles of (23 1P04/2 are 4.45 81026