Question

010 (10 points) The tar contents of 10 brands of cigarettes selected at random from the latest list released by the Federal Trade Commission are as follows: 73 8.6, 104, 16.1, 122, 15.1, 145, 12.9, 11.8 and 9.3 milligrams Calculate the sample mean, the sample median, the sample variance, and the sample standard deviation + Drag and drop your images or click to browse

some help please

Answer 1

Solution - Samples (xi) 20.4304 10.3684 8.6 10.4 16 12.2 15.1 14.5 12.89 (xi- ² - 4.52 -3.22 -1.42 4.28 0.38 3.28 2.68 1.08 -0.02 -2.52 2.0164 18.3184 0.1444 10.7584 7.1824 1.1664 0.6004 6.3504 76.736 9.3 Total = 118.2 (sample) Find sample mean = x Here in total numbers of observation n=10 À = sum of all observation Total number of observation 118.2 ň = 11.82 kind sample median. First arrange the observation 7.3 8.6 9.3 10.4 11.8 14.5 15.1 16.1. in a increasing order. 12. 2 , 12.9 Here n=10 - even) formua for a median (when median = 2th obs? + (n n is even) is )th obs? 2

median (10)th obs² + 1 19 + 17th obs? + 6th obsn 5th obs" 2 = + 12.2 11.8 2 Median = 12 Sample variance 62 8² = (xi - x)² ... (calculated in a table) = 76.736 10-1 = 76.736 o² = 8.5262 sample standard deviatich =0 T= 1 a = √8.5262 6=2.8 1997 N