Question

4 Mole Calculations II D. What is the mass of 4.50 x 1022 atoms of gold, Au? (a) 0.0679 g (b) 0.0748 g 13.3 g 14.7 g 2640 g 1. RECORD THE SAME ANSWER AGAIN. 2. RECORD THE SAME ANSWER AGAIN.

Answer 1

The atoms of gold(Au) = 4.50 x 10²² atoms

Calculate the number of moles of gold atoms using the Avagadro's number as follows:

= 4.50 x 10²² atoms x [1 mol Au / (6.022 x 10²³ atoms)]

= 0.07473 mol Au atoms

Use the moles of Au and molar mass of gold(Au) and determine the mass of gold as follows:

= 0.07473 mol Au atoms x [196.97 g / 1 mol]

= 14.7 g

Thus, the mass of 4.50 x 10²² atoms of gold, Au is 14.7 g.

Thus, option (D) 14.7 g is the correct answer.