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all I need is sample formula for each row the morality of acid and bases are all 1.000M
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Answer #1

CHU+ NaH) Part A Run #1 50 mL. 25 +25) mL 1. Totl volume of Solution 50 mL x 19 lml 6.37 C mx Cx 4T- 50 x4124 Jx6.37 C volume x dunaty Total mn (29.20-22.93) C 2.4T 3. 9 1331 Joules 1 Malardy 4. Number of mles of limihng Tesgent Volume in Liters x 0 025 Lx uo M) 1331/0-025 53 246 J/ue ster m 53-24 KJ)mlu J/ne 5. AH= THeN Run #2- 1. Jatal mans of Selutim 2. OT (29 80- 23.03) C= 6.77 e. 3.9,=50q x 4-184 J 6-77.C-1416 Joulay. 4.Numbers of males of limihngYhageut 5. 4H= 14l6 J /6.015 ma 56646 J/me 56.64 KJlme (53-24 + 5-64) KT/e 54.9u klmda Asage 4H 2

(Mg S042 of Solurtian 2. AT(26-40-16-80) 'C9 6.e mx CX4T Part b 9t 300g -3109 I. Jo tul mn 12440 Jouks 3 10 a x 418 J 3 4= X9.6.C 4 Moles of Solid 10-09/4-9 (120qlm) O'0833 le 147 kJ Imle 12240 J/D:0833 M4S04 7H0 I. J6tnl men (25-2-W7 of Solution 3022 69 -121C 1. OT- (4.30-IS 51) 3022-6 ax 4-18 x(-l-21 )-15288 Jouly 4 Males of Solid22.69/246 9/mu)0.092 m 54H--I528 J/0-092 17 (66 KJlmne mnay

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Answer 1

CHU+ NaH) Part A Run #1 50 mL. 25 +25) mL 1. Totl volume of Solution 50 mL x 19 lml 6.37 C mx Cx 4T- 50 x4124 Jx6.37 C volume x dunaty Total mn (29.20-22.93) C 2.4T 3. 9 1331 Joules 1 Malardy 4. Number of mles of limihng Tesgent Volume in Liters x 0 025 Lx uo M) 1331/0-025 53 246 J/ue ster m 53-24 KJ)mlu J/ne 5. AH= THeN Run #2- 1. Jatal mans of Selutim 2. OT (29 80- 23.03) C= 6.77 e. 3.9,=50q x 4-184 J 6-77.C-1416 Joulay. 4.Numbers of males of limihngYhageut 5. 4H= 14l6 J /6.015 ma 56646 J/me 56.64 KJlme (53-24 + 5-64) KT/e 54.9u klmda Asage 4H 2

(Mg S042 of Solurtian 2. AT(26-40-16-80) 'C9 6.e mx CX4T Part b 9t 300g -3109 I. Jo tul mn 12440 Jouks 3 10 a x 418 J 3 4= X9.6.C 4 Moles of Solid 10-09/4-9 (120qlm) O'0833 le 147 kJ Imle 12240 J/D:0833 M4S04 7H0 I. J6tnl men (25-2-W7 of Solution 3022 69 -121C 1. OT- (4.30-IS 51) 3022-6 ax 4-18 x(-l-21 )-15288 Jouly 4 Males of Solid22.69/246 9/mu)0.092 m 54H--I528 J/0-092 17 (66 KJlmne mnay