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![- 2m 223.07 ) 1 kmol + 2y 69.9) k mol - [ $(196.41 .) + 1 mol(205.19 ore] = 466.16 { + 139.62 – 747.54 -205.14. = -346.82 T](http://img.homeworklib.com/questions/a3daafe0-341a-11ea-a206-c782f82f8c59.png?x-oss-process=image/resize,w_560)
SO AT T1 reaction will be spontaneous because delta g is negative.
At T2 reaction will be non spontaneous because delta g is positive.
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(3 Points) Calculate the standard Gibbs energy of reaction for the reaction below at 298 K...
no. 3 COL LUPIC. 3. (20 pts) Use the following thermodynamic data (reported at 298 K...
no. 3
COL LUPIC. 3. (20 pts) Use the following thermodynamic data (reported at 298 K and 1 bar) to determine: Substance 4/Hº (kJ/mol) S. (I/K-mol) 4,6° (kJ/mol) N2H4(1) 50.53 121.21 149.4 159.4 N2H4(g) 95.4 Wap 238.9 205.14 191. 610 O2(g) 0 0 N2(g) H2O(1) -237.2 69.91 -285.83 SpA (3a) (5 pts) The molar enthalpy of vaporization of hydrazine N, H. (36) (5 pts) Whether liquid hydrazine vaporizes at 25°C and 1 bar? Hint: Calculate the free energy of vaporization...
Gibbs Free Energy Change Homework – Unanswered Use the data to determine the Gibbs Free Energy...
Gibbs Free Energy Change Homework – Unanswered Use the data to determine the Gibbs Free Energy change AGrxn for this process: Ca(OH)2(s) + 2NH4Cl(aq) = 2NH3(g) + 2H2O(1) + CaCl2(s) at 4°C. Substance CaCla(s) Ca(OH)2 NH3) NHCl(aq) HjO(0) ΔΗ: (kJ/mol -795.8 -986.09 -46.11 -299.66 -285.83 S (J/mol K) 104.6 83.4 192.45 169.9 69.91
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations...
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations 213) substance! ΔG。 kJ/mol N2O4(g) +99.8 NO2(g)+51.3 1.13 0.32 3.1
Calculate the standard Gibbs energy of the following reaction at T = 298.15 K using the...
Calculate the standard Gibbs energy of the following reaction at T = 298.15 K using the data given below. 2 CH3CHO(g) + O2(g) ® 2 CH3COOH(l) Som(CH3COOH(l)) = 159.8 J K–1 mol–1 DfHo(CH3COOH(l)) = –484.5 kJ mol–1 Som(CH3CHO(g)) = 250.3 J K–1 mol–1 DfHo(CH3CHO(g)) = –166.19 kJ mol–1 Som(O2(g)) = 205.14 J K–1 mol–1
What is the standard reaction Gibbs energy at 298 K for the following reaction of lactic...
What is the standard reaction Gibbs energy at 298 K for the following reaction of lactic acid, C3H6O3(s) + O2(g) → 3CO2(g) + 3H2O(l)
5. The standard molar entropy of liquid ethanol (C2H5OH) is 160.7 J K mol and the...
5. The standard molar entropy of liquid ethanol (C2H5OH) is 160.7 J K mol and the standard enthalpy of combustion is - 1368 kJ mol at 298 K, how much is the standard Gibbs energy (A,Gº) of formation of liquid ethanol at 298 K? (20 pts) The formation reaction of ethanol is 2C (graphite) + O2(g) + 3H2 (g) → C2H5OH() The combustion reaction of ethanol is CH5OH (1) + 302 (9) ► 200, (g) + 3H20 (1) CO; (g)...
A reaction is at equilibrium at 298 K. At 310 K, the Gibbs free energy for the reaction is –12.6 ...
A reaction is at equilibrium at 298 K. At 310 K, the Gibbs free energy for the reaction is –12.6 kJ/mol. Assuming that both entropy and enthalpy are independent of temperature, what are the values of the entropy and enthalpy for this reaction?
Calculate the standard Gibbs energy change for the following generic reaction at 298 K, using the...
Calculate the standard Gibbs energy change for the following generic reaction at 298 K, using the standard enthalpies of formation and standard entropies from the table below A+B-C AHI KJ SI JKT Substance mor1 mor1 148.0 299.0 0 76.2 -269.9 105.3 Select one: O a. 8.001e4 kJ/mol O b.-337.5 kJ/mol O C.-265.1 kJ/mol O d. 382.9 kJ/mol o e.-3.460e4 kJ/mol
correct answer? The change in Gibbs free energy, AGⓇ for the following reaction at 298 K...
correct answer?
The change in Gibbs free energy, AGⓇ for the following reaction at 298 K is 70.6 kJ/mol. 2NO,(9) — 2NO(g) + O2(9) What is Keq for this reaction? O 4.30 O 0.971 2.00 1.03 O 0.936
) Use standard Gibbs energies of formation to calculate the standard reaction Gibbs energies at 298...
) Use standard Gibbs energies of formation to calculate the standard reaction Gibbs energies at 298 K of the reactions (i) Zn(s)+Cu2+ (aq) → Zn2+ (aq)+Cu(s) (ii) C12H2201(s)+1202(8)-12CO2(g)+11H2O0)
no. 3
COL LUPIC. 3. (20 pts) Use the following thermodynamic data (reported at 298 K and 1 bar) to determine: Substance 4/Hº (kJ/mol) S. (I/K-mol) 4,6° (kJ/mol) N2H4(1) 50.53 121.21 149.4 159.4 N2H4(g) 95.4 Wap 238.9 205.14 191. 610 O2(g) 0 0 N2(g) H2O(1) -237.2 69.91 -285.83 SpA (3a) (5 pts) The molar enthalpy of vaporization of hydrazine N, H. (36) (5 pts) Whether liquid hydrazine vaporizes at 25°C and 1 bar? Hint: Calculate the free energy of vaporization...
Gibbs Free Energy Change Homework – Unanswered Use the data to determine the Gibbs Free Energy change AGrxn for this process: Ca(OH)2(s) + 2NH4Cl(aq) = 2NH3(g) + 2H2O(1) + CaCl2(s) at 4°C. Substance CaCla(s) Ca(OH)2 NH3) NHCl(aq) HjO(0) ΔΗ: (kJ/mol -795.8 -986.09 -46.11 -299.66 -285.83 S (J/mol K) 104.6 83.4 192.45 169.9 69.91
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations 213) substance! ΔG。 kJ/mol N2O4(g) +99.8 NO2(g)+51.3 1.13 0.32 3.1
5. The standard molar entropy of liquid ethanol (C2H5OH) is 160.7 J K mol and the standard enthalpy of combustion is - 1368 kJ mol at 298 K, how much is the standard Gibbs energy (A,Gº) of formation of liquid ethanol at 298 K? (20 pts) The formation reaction of ethanol is 2C (graphite) + O2(g) + 3H2 (g) → C2H5OH() The combustion reaction of ethanol is CH5OH (1) + 302 (9) ► 200, (g) + 3H20 (1) CO; (g)...
Calculate the standard Gibbs energy change for the following generic reaction at 298 K, using the standard enthalpies of formation and standard entropies from the table below A+B-C AHI KJ SI JKT Substance mor1 mor1 148.0 299.0 0 76.2 -269.9 105.3 Select one: O a. 8.001e4 kJ/mol O b.-337.5 kJ/mol O C.-265.1 kJ/mol O d. 382.9 kJ/mol o e.-3.460e4 kJ/mol
correct answer?
The change in Gibbs free energy, AGⓇ for the following reaction at 298 K is 70.6 kJ/mol. 2NO,(9) — 2NO(g) + O2(9) What is Keq for this reaction? O 4.30 O 0.971 2.00 1.03 O 0.936
) Use standard Gibbs energies of formation to calculate the standard reaction Gibbs energies at 298 K of the reactions (i) Zn(s)+Cu2+ (aq) → Zn2+ (aq)+Cu(s) (ii) C12H2201(s)+1202(8)-12CO2(g)+11H2O0)
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