Question

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used here are for illustrative purposes. The data you obtain will be different. Note: The data used DETERMINATION OF SULFATE Record all mas of double salt user EXAMPLE: The mass of double sulfate weigh 2.178 il mass measurements made in the sulfate determination. Report the mass le salt used and the mass of barium sulfate obtained. LE The beaker weighs 97.033 g: the beaker and double salt weigh 98.111 g; the Jouble salt is 1.078 g; the filter paper weighs 0.956 : the filter paper and barium weigh 2.178 g; the mass of barium sulfate is 1.222 g PRACTICE: The be ICE. The beaker weighs 103.285 g; the beaker and double salt weigh 104.397 g: aper weighs 0.972 g; the filter paper and barium sulfate weigh 2.318 g. the filter paper weighs 0.972 g: the above results to determine the mass of sulfate in the barium sulfate sample. Use the above results to determ EXAMPLE: 0.5030 g PRACTICE: Use the above results to determine the mass percent of sulfate in the double salt. EXAMPLE: 46.66% PRACTICE: B. DETERMINATION OF WATER Record all mass measurements made in the water determination. Report the mass of double salt used and the mass of water lost on heating. EXAMPLE: The crucible weighs 11.034 g; the crucible and double salt weigh 12.246 g: the mass of double salt is 1.212 g; the crucible and anhydrous double salt (after heating) weigh 12.001 g; the mass of water lost on heating is 0.245 g. PRACTICE: The crucible weighs 9.691 g; the crucible and double salt weigh 10.816 g; the crucible and anhydrous double salt weigh 10.675 g. use the above results to determine the mass percent of water in the double salt. EXAMPLE: 20.2% PRACTICE:

Answer 1

cot. of beaker = 103.285 Cotcy beaker & double salt = 104.3972 actual weight of double salt = 104.397 - 107.285 = /•/129 totul mass of double salt = 1.1129 usty the results given below for Soy amount - 0.5536 x 100 7. suy = T1112 6 oft hydrytep double salt = lood16-9.691) = 1.125g I weigt ay anhydrous salt = (10.675-9,691) 2 = 0.98 4 9 amount of water a fost ef hydrath - (wth anlayday - 1.125 -0.984 → olay % y 120 = 0.141 49.78% $117/ weiget af filter pypest = 0.972g weight of filter paper + Basoy = 2.31 I actul weigt af Basuya (2.318-01972 = 1.346 I I wif we have 237.38 g, in Imol Basoy, ie this son amort 1.125 12.5% is 96 g. so amount of soy in 1.741 g pasoy = 96 x 1.746 937'18 015596g.