Assuming water boils at 100 degree Celsius, when we provide more heat water will get converted into steam (vapor form)
So to find the heat required
Q = m* Hvap
Q= amount of heated added
m= mass of water
Hvap = latent heat of vaporization
We use latent heat of vaporization because water is being converted into steam , if it had been converted into ice we would have used latent heat of fusion.
But in this case we will always use latent heat of vaporization.
Step 2: How much energy does it take to completely vaporize the boiling water? This is...
1. How much energy (in kJ) is required to completely vaporize 200.g of 25.0*C liquid water? Step 1: How much energy does it take to get the water from 25.00°C to boiling? This where you use Qumc(TFT) because this part is just a heat flow problem, not a phase change like the next part.
how much heat does it take to completely vaporize a 75.0g ice cube? given: ice = 0°C T boiling point = 100°C C water = 1cal/g°C Lf = 80.0 cal/g Lv = 540.0 cal/g
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