The equilibrium constant for: F2(g) + 2HBr(g) ↔ 2HF + Br2 , is 1.0 x 10-5....

Question

Question

The equilibrium constant for: F2(g) + 2HBr(g) ↔ 2HF + Br2 , is 1.0 x 10-5. The equilibrium lies:

A.	to the left (mostly reactants)
B.	to the right (mostly products)
C.	in the middle (50% reactants, 50% products)

science chemistry

Answer 1

Answer #1

Equilibrium: F(g) + 2HBr (g) 2 2HF(8) + Bry(8) ; K= 1.0x10-4 When the value of equilibrium constant is more than 1, the forwa

Answer 2

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