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How much concentrated solution would you take to prepare 2.85 L of 0.495 molL−1 HCl by...

How much concentrated solution would you take to prepare 2.85 L of 0.495 molL−1 HCl by mixing with water?

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Answer #1

The concentration of commercial HCl is 37.2 % and molarity is 12.06 M (obtained from Sigma Aldrich website)

We can use following formula

Va x Na = Vb x Nb

Va = 2.85 L N = 0.495 M Vb = ? Nb = 12.01 M

Substitute the values and calculate

Nb = 2.85 L x 0.495 M / 12.01 M = 0.1174 Liter ot 117.4 ml

Hence we can take 117.4 ml of 12.01 M HCl (Concentrated or commercial HCl) and made up to 2.85 L to give 0.495 M

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