Question

BALANCE and FIND the half-reactions for this Redox Reaction, then indicate which substances are Oxidizing Agents, and Reducing Agents.

Fe^3+(aq) + NH2OH2+(aq) = Fe^2+(aq) + N2O(g)

Answer 1

The substance oxidised is called reducing agent and the substance reduced is called oxidising agent.

Coq) + NH₂OH, Fe & Ngon cag) --> Wribe the Oxidation number Fe, N in the equator هنطهيه Fe & NH₂OH – Fe2+ & NO NH₂OH₂ : N 2 + 4C+1)+L-2)=+1 X®N= -1 Reduction NO Increase in oxidation number it oxidation 2x + (-2) = 0 Decrease in oxidation number is Reduction) x=+1 ~ Divide the equation into two halves oxidation Reduction 2+ NH₂ OH - Ngocg Ford 3 cagi (ag) Balance all the elements except HiO 2NH₂OH - N₂0 Festa Fe cap) To balane H. o add it, and to balance ö add H₂O 2NH₂ 0 Hz Coa + 24 N₂O + H₂0 Fets lag ke taas Balance charge for Change oxidation Number & N:2 bein oxidation Change in for en change is 4 number of Fe ix 1 2NH2O Hyt + 2*--> N20+ H20 + 4é Fette -> Fete Socaq ' Equalize the electrons by multiplying with suitable nomba, 1x 90 ZNI OH2 + 2H+ - N₂O + H2O + 46 4* 490 4Fet3 + 4e" - 4F.com Balanced 45 +3 + 2NHOH+ + 24 - 45e & NO +H₂O 2012 cagay Cag) 2097 9 2 ) +3 cogs * Can +2 Equation

Here Fe^{​​​​​ 3+} is reduced. So oxidising agent is Fe ³⁺

NH_{​​​​2}OH₂⁺ is oxidised . So reducing agent is NH₂OH₂⁺