Question

The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 2.126 g sample of ether was combusted in an oxygen rich environment to produce 5.049 g of CO, (g) and 2.584 g of H,O(g). Insert subscripts to complete the empirical formula of ether. empirical formula: CHO

Answer 1

Empirical formula : C₄H₁₀O

Explanation

mass CO₂ = 5.049 g

moles CO₂ = (mass CO₂) / (molar mass CO₂)

moles CO₂ = (5.049 g) / (44.01 g/mol)

moles CO₂ = 0.1147 mol

moles C = moles CO₂

moles C = 0.1147 mol

mass C = (moles C) * (molar mass C)

mass C = (0.1147 mol) * (12.01 g/mol)

mass C = 1.378 g

mass H₂O = 2.584 g

moles H₂O = (mass H₂O) / (molar mass H₂O)

moles H₂O = (2.584 g) / (18.01528 g/mol)

moles H₂O = 0.1434 mol

moles H = 2 * (moles H₂O)

moles H = 2 * (0.1434 mol)

moles H = 0.287 mol

mass H = (moles H) * (molar mass H)

mass H = (0.287 mol) * (1.008 g/mol)

mass H = 0.289 g

mass O = (total mass) - (mass C + mass H)

mass O = (2.126 g) - (1.378 g + 0.289 g)

mass O = 0.4588 g

moles O = (mass O) / (molar mass O)

moles O = (0.4588 g) / (16.0 g/mol)

moles O = 0.028677 mol

moles C / moles O = (0.1147 mol) / (0.028677 mol)

moles C / moles O = 4

moles H / moles O = (0.287 mol) / (0.028677 mol)

moles H / moles O = 10

There are 4 atoms of C and 10 atoms of H per one atom of O

Empirical formula : C₄H₁₀O