a)
let us consider "d" is the distance left to point 1
now, in order to get net electric force at that point to be zero, magnitude of both the electric field must be equal so that they cancel out each other hence we must equalise electric field due to charge 1 and charge 2 at that point,
so,
k q1 / d^2 = k q2 / (L+d) ^2
q2/q1 = [ (L +d) / d ] ^2
2.97 / 0.98 = [ 10.9 / d +1 ] ^2
d = 14.71 cm
x coordinate of this point = - 14.71 cm ( Ans)
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b) since all the calculations are carrying out in x axis, so y co ordinate must be 0
y = 0 ( Ans)
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do comment in case any doubt, will reply for sure.. Goodluck
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Chapter 21, Problem 013
In the figure particle 1 of charge q1 = 0.97
μC and particle 2 of charge q2 = -2.91 μC, are
held at separation L = 9.8 cm on an x axis. If
particle 3 of unknown charge q3 is to be
located such that the net electrostatic force on it from particles
1 and 2 is zero, what must be the (a)x
and (b)y coordinates of particle 3?
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