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PRINTER VERSION BACk NE Chapter 02, Problem 08 GO An 18-year-old runner can complete a 10.0-km course with an average speed of 4.52 m/s. A 50-year-old runner can cover the same distance with an average speed of 3.86 m/s. How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner? Number Units the tolerance is +/-5% GO TUTORIAL LINK TO TEXT LINK TO TEXT
Chapter 02, Problem 10 In reaching her destination, a backpacker walks with an average velocity of 1.03 m/s, due results, because she hikes for 5.53 km with an average velocity of 3.34 m/s due west average velocity of 0.479 m/s due east. How far east did she walk (in kilometers)? west. This average velocity turns around, and hikes with an West I East Number Units the tolerance is +/-5%
hapter 02, Problem 19 GO The initial velocity and acceleration of four moving objects at a given instant in time are given in the following table. Determine the final speed of each of the objects, assuming that the time elapsed since t 0 s is 2.1 s. Initial velocity vo +12m/s + 12m/s - 12m/s Acceleration a +2.6m/s -3.5m/s +3.2 m/s -3.0m/s? 13m/s (a) Final speed - (b) Final speed (c) Final speed - (d) Final speed-
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Answer #1

Problem-8

Given is:

Distance of the course = 10 km or  104m 7n

speed of the old runner  so-3.86m/s

speed of the young runner  Sy = 4.52m/s

Now,

the time taken by old runner to complete the course is

distance time = speed

by plugging all the values we get

104 o 3,86

which gives us

t, 2590.67~ 2591s

Similarly time taken by the young boy is

104 y4.52 3

y 2212.39 2213s

Thus

the time difference is

to-ty-2591-2213

378

Hence,

the younger boy should start the race 378 seconds later than the old runner to finish the line at the same time

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