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#include <iostream>
#include <array>
using namespace std;


int specific_pattern(short pattern[], int size) {
   int pattern_found = -1;
   for (int i = 0; i < size; i++) {
       for (int j = i; j < size; j++) {
           if ((pattern[j] - pattern[i]) == 20) {
               for (int k = j; k < size; k++) {
                   if ((pattern[k] - pattern[j]) == 20) {
                       return i;
                   }
               }
           }

       }
   }

   return pattern_found;
}


int main() {
   short data[] = { 10,20,31,40,55,60,65525 };
   cout << specific_pattern(data, (sizeof(data) / sizeof(data[0]))) << endl;
   return 0;
}

My code from Problem 3 is printed above in bold. I need help understanding this problem. In C++ please.
1-1-0 Detection: Modify Problem 3 such that it returns the index of the beginning of a sequence where the first two elements

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Homework Answers

Answer #1

This is modification in problem 3 as 1-1-0 Detection.

#include <bits/stdc++.h>
#include <array>
using namespace std;


int specific_pattern(short pattern[], int size) {
int pattern_found = -1,flag=0,i;
for ( i = 0; i < size; i++) {

if ((pattern[i+1] - pattern[i]) == 20) {
for (int k = i+2; k < size; k++) {
if ((pattern[k] - pattern[i]) == 40) {
flag=1;
}
}
}

}
if(flag==0)
{
return i;
}

return pattern_found;
}


int main() {
short data[] = { 20,40,31,40,55,60,6525 };
cout << specific_pattern(data, (sizeof(data) / sizeof(data[0]))) << endl;
return 0;
}

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