Question

4- Calculate the concentration of mercur ians and iodide ions in equilibrium with mercury (I) iodide.

Answer 1

Answer:

Dear Student,

The equilibrium reaction between Hg₂I₂ and their ions in equilibrium with solid product are related by the following relations;

Hg₂I₂ <=> Hg₂²⁺ + 2I^-

and K_sp = [C_Hg+][C_I-]² = 5.2 x 10^-29

Hence, the Ceq (equilibrium concentration) are related to Ksp as follow;

K_sp = C_eq. (2C_eq)² = 4C_eq³

C_eq = (K_sp/4)^1/3 = 2.35 x 10^-10 M

Hence, the concentration of Hg₂²⁺ ions is 2.35 x 10^-10 and I^- will be twice of Hg₂²⁺ = 4.70 x 10^-10 M. When the equilibrium will be established.

Please check the actual (or more accurate) value in the provided text books.

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Thanks