The position of a rabbit along a straight tunnel as a function of time is plotted...
The position of a rabbit along a straight tunnel as a function of time is plotted in the figure.
a.) What is its instantaneous velocity at t=10.0s?
b.) What is its instantaneous velocity at t=30.0s?
c.) What is its average velocity between t=0 and t=5.0s?
d.) What is its average velocity between t=25.0s and t=30.0s?
e.) What is its average velocity between t=40.0s and t=50.0s?
Homework Answers
-(a) Make a tangent line at t = 10 s to find the instantaneous velocity by its slope. This is the less steep of the two blue lines above. This line seems to have a slope of rise/run = 14 m/50 s = .28 m/s
-(b) Make a tangent line at t = 30 s, and find its slope (this is the velocity). This is the steeper of the two blue lines. This line rises 25 m between 17 and 37 seconds, so it has a slope of about 25 m/20 s, which is about 1.25 or 1.2 m/s.
-(c) Average velocity is just total displacement divided by total time. From 0 to 5 seconds it seems to go from 0 to about 1.5 m (read from the graph), and the time is of course 5 seconds, so the average velocity is 1.5 m/5 = .3 m/s
-(d) From 25 to 30 the rabbit displaces from 8 m to 16 m (read from the graph), again in 5 seconds giving an average velocity of 8m/5 s = 1.6 m/s
-(e) From 40 to 50 seconds the rabbit displaces from 20 m to 10 m (read from the graph), now in 10 seconds giving an average velocity of -10m/10s = -1.0 m/s
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