Question

3) Current-carrying Straight Wires - Magnetic Field Nearby In these cases, long, straight wires that are perpendicular to the page are carrying electric currents into the page. Wire W Wire W Wire W- --Wire W 2 AP 2A 2A 2A P P ZAP tong sampung ----- ---- his 0 eded Rank the strength (magnitude) of the magnetic field at P due to wire W. Explain your reasoning. @ BM --- 12501 01 1291893 moitalnomgoz stw od no 90101 pisongsmodi to (obutings) dignotla odio ghino2591 oy nislqxd 4) Pairs Of Long Current-carrying Wires - Magnetic Field Nearby In these cases, the two parallel wires have the same magnitude current perpendicular to the plane of the page. The direction of the current in each wire is shown.. A culo P 0 0 * sul vd 1678 og pil Cut P 0 * o t fait O sub go wollt a *120 babua A Rank the magnitude of the magnetic field at point P. Explain your reasoning. od nie bra moldogs Videobloggibod diw moldogan0 tanolts ai dT. madi 109 110

Answer 1

Solution - 3 fig. A AZ - -- - current 1 : 2A Axis -z is į current into the l out of plane / page . Magnetic field at a point due to long wire is given by: Bio. Sawarts law B = 40[7 perpendiculante space 120d) llo = 48 x167 H/m -> absolulē bermeablity of d. - berpendicular distance. 1. of pourt p from long Straight wire Hence, Magnetic field at point .p due to left long straight wire = B,

Bi = Mo I l towards -y axis) 2nd llo 2 2nd Il Direction can y be found out, I using Right Magnetic field | Hand Thumb . Rule at p due to right wire. - = B2 = 402, . ( toward ty Net magnetic field at p Bnet = Bit B2 = -lo2t 102 Zid axis ) .. 2nd 25d Bnet zo fig-B 2A 2 Ard 24 - - r -o-knd> - wire 1 wire-2 .

( towarde Magnetic field at p due to Wire - 1 = B, B = 40 [. + 27 (20) ay aris) Magnetic field at p due to wire-2. = B2 25 Coul Br = lot rds (toy axis) Net magnetic field at p 3 Bnet - B+B . I=2 Bnet = 240. + 4llo . und a 1:640, 7 7 I und towards y aris

I do wire 1 wire-2 Magnetic field at point due to .4A wire-1 p 20x(24) lund / towards - y antes point ? Magnetic field at due to wire-2 Boleh tenaga dalam towards - yaxis Net magnetie field at point P Bnet = By + 8 yod and Geot yello U Bet urd towards -y axis

f out of the . fig. -ing 6A P 64 by. dita Magnetic field due to 4A carry- wire at po = B = 40x4 T 12ad B) - Sale in s Magnetic field at p due to b e carrying wire: - By – 4o [ 1464677 zad zad , to 64 carrying Net magnetic = Bnet = towards + y ases field at i -B1 + B2 Un iod 20d = 646 - 2012 21

2nd und Bret = 211 . ş towards ty axis ) - ta 5 . (iv) from equation (°), i) , cüis &(iv) magnitude of magn- - etic field can be ranked. Magnitude ofis magnetic field at ė :- | Bnet of fig. c > Briet of fig.B> Bret of figo) Buet of fig A.