Question

3. In the figure to the right the electric field components are Ex-a x1/2 and E,-E,-0 with a-135 N/C/m1/2. Calculate (a) the flux through the cube and (b) the charge within the cube. The cube has a sides of length L20 cm and is a distance L from the origin with one edge coincident with the x-axis as shown.

Answer 1

Given That a) Electric Flux parallel to y and z axis will be zero as electric Field along y and z axis is zero Electric field at left face EL = aL^1/2 = 135 times (0.2)^1/2 = 60.37 N/c Electric flue at that face QL = -EL times A = El times L^2 = 60.37 times (0.2)^2 = -2.41 N middot m^2/c Electric field at right face ER = a(2L)^1/2 = 135(2 times 0.2)^1/2 = 85.38 N/c Electric flux at that face straightphi R = + ER xL^2 = + 85.38 times (0.2)^2 = 3.42 N - m^2/C Net flux straightphi net = straightphi_L + straightphi_R = -2.41 + 3.42 = 1.01 N - m^2/c straightphi_net = 1.01 N - m^2/C \r\n Gauss�s law straightphi = a_in/ epsilon_0 straightphi_in = straightphi times epsilon_0 = 1.01 times 8.85 times 10^-12 = 8.94 times 10^-12 c a_in = 8.94 times 10^-12 c