Given that the heat of fusion of water is +6.02 kJ/mol, that the heat capacity of...

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Given that the heat of fusion of water is +6.02 kJ/mol, that the heat capacity of...

Given that the heat of fusion of water is +6.02 kJ/mol, that the heat capacity of H2O(l) is 75.2 J/mol⋅K and that the heat capacity of H2O(s) is 37.7 J/mol⋅K, calculate the heat of fusion of water at -14 ∘C.

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Answer 1

Answer #1

uvater) fos bmall chane in terpenat une

Hence entropy, S = - 20.075 JK-1mol-1

T = 259 K

S = Hf / T(K)

=> - 20.075 JK-1mol-1 = Hf / 259 K

=> Hf = - 20.075 JK-1mol-1 x 259 K = - 5.20 KJ/mol (answer)

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Answer 2

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