A 6.52 g sample of copper is contaminated with an additional 0.75 g of zinc. Suppose...
A 6.52 g sample of copper is contaminated with an additional 0.75 g of zinc. Suppose an atomic mass measurement was performed on this sample.
What would be the measured atomic mass?
Homework Answers
you need to find the fraction of copper and zinc and multiply it with the mass respectively
hence fraction of copper is 6.52/7.27 and multiply with mass of copper
so (6.52/7.27) * 63.55 = 56.993
in the same way calculatee for zinc (0.75/7.27) * 65.38 = 6.744
so the measured atomic mass is 56.993 + 6.744 = 63.737
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