Question

6. Identify the following: a. An-excited state of this element has the electron configuration 1s 2s 2p Beryllium b. The ground-state electron configuration is [Ne]3s 3p Sulfur c. An excited state of this element has the electron configuration [Kr5s4dº5p 6s' Silver d. The ground-state electron configuration contains 3 unpaired 5p electrons

Answer 1

We know in ground that for any element noumber of electron state is equal to number of election in exited state. a) excited state electron configuration of element - 15² 25'2p' so total number of electron = 4 so In Beryllium , there are 4 election present. ground state electron configuration - [Ne] 8523p4 total number of election 10+2+4 - 16 So, there are 16 electrons in Sulfur element. c) excited electron configuration is - [kr] 5s² ud sp²65' total number of electron - 36 +2 +6+2+1 = 47 so, there are 47 electron in Silver (Ag). C) ground state electron configuration contains 3 unpaired spelechons. means it has configuration 5p. So, this element belong to p.block and of 5th period. fifth period p-block elements are In, Sn, Sb, Te, I In it sbie. Antimony ends with sp3 configuration. so, the unknown element with 3 unpaired sp electron is Antimony.