Question

Consider a point charge q completely enclosed by a Gaussian surface. What happens to the total flux through the surface if I keep the charge inside but decrease the size of the Gaussian surface and move the charge to a different location?

Question 3 (1 point) Consider a point charge q completely enclosed by a Gaussian surface. What happens to the total flux through the surface if I keep the charge inside but decrease the size of the Gaussian surface and move the charge to a different location? Not enough information given. It goes to zero The electric flux decreases It stays the same.

Answer 1

From Gauss Law of electricity, Electric flux phi = 1/epsilon_0 (Net charge enclosed by the Gaussian surface) In our problem charge does not charged, but its location charged with in the Gaussian surface. Therefore electric flux does not charged. Therefore Last option ie, It stays the same is correct.