Question

Strontium chloride and sodium fluoride react to form strontium fluoride and sodium chloride, according to the reaction shown. SIC, (aq) + 2NaF(aq) — SrF,() +2 NaCl(aq) What volume of a 0.290 M NaF solution is required to react completely with 307 ml. of a 0-160 M SCI, solution? volume 280.68 How many moles of SIF, are formed from this reaction? moles of SIF: 04912

Answer 1

To find the volume of 0.290 M NaF solution Given that 307 mL of a 0.160 MSrCl, solution chemical reaction SrCl, (aq) + 2NaF (aq) →SF, (s) +2NaCl(aq) First find the moles of SrCl, solution 307 mL = 0.307L moles = molarity x volume = 0.160m 01/L x 0.307L = 0.04912moles find the moles of NaF According to reaction NaF and SrCl, is 2:1mole ratio 1 2 moles of NaF Therefore moles of NaF = 0.04912moles of Srci, = 0.09824moles of NaF 1 mole of SrCl, To find the volume of NaF volume- moles molarity 0.09824moles 0.290 mol/L = 0.338L = 338mL Hence the volume of 0.290 M NaF solution = 338mL To find the moles of SIE, According to reaction SrF, and SrCl, is 1:1mole ratio Therefore moles of SrF, = 0.04912moles Hence the moles of SrF, = 0.04912moles