Question

10. An proton-antiproton pair is produced by a 2.10×1032.10×103 MeV photon. What is the kinetic energy of the antiproton if the kinetic energy of the proton is 55.95 MeV?
Use the following Joules-to-electron-Volts conversion 1eV = 1.602 × 10^-19 J.
The rest mass of a proton is 1.67×10−271.67×10−27 kg.
MeV

Answer 1

Solution: Given data? Cergy of photon (E) = 2.10 X 1032.10 x 103 Mey = Kinetic energy of proton (kp) = 55.95 MeV rest mass of proton and antiproton (m) = 1.67 8 10 kg com energy conservation Griergy of photon = (Energy of proton and antiporten due to mass) (Kinetic energy of proton and antiproton) E = mc2t met Rot Rap --- Here c = -67 X1021) Va cº here 1067x16** kg = 938.28 mer mc² = 9.38.28 Men ez . mc² = 938.28 mer put all values in eance 223243.23 Mev = 938.28 Mev +938-28 Mev+55.98 Mev tkap Kap = 2213 10:69 mer Kap = 221.31 x 103 mev 103 mew=Gev Krp = 221-3) Gev Answer