
Suppose a 250. mL flask is filled with 1.0 mol of Br,, 1.5 mol of OCI,...
Suppose a 500 ml flask is filled with 0.10 mol of Bry, 1.6 mol of OCI, and 0.60 mol of BrCl. The following reaction becomes possible: Bry()+OCI (8) -BrOCI () + BrCl() The equilibrium constant K for this reaction is 0.770 at the temperature of the flask Calculate the equilibrium molarity of OCI. Round your answer to two decimal places x x 5 ?
Suppose a 250. mL flask is filled with 2.0 mol of Br2, 1.1 mol of OCI, and 0.80 mol of BroCl. The following reaction becomes possible: Br2(g) + Oci (g) Broci (g) + Brci(g) The equilibrium constant K for this reaction is 0.624 at the temperature of the flask. Calculate the equilibrium molarity of BroCl. Round your answer to two decimal places. Пм xs ?
Suppose a 500 ml flask is filled with 0.40 mol of Bry, 1.3 mol of OCI, and 1.1 mol of BrOCI. The following reaction becomes possible: Bry()+OCI,() BrOCI()+BCI) The equilibrium constant for this reaction is 2.95 at the temperature of the flask. Calculate the equilibrium molarity of Br. Round your answer to two decimal places.
= Objective Knowledge Check Question 12 Suppose a 250 ml flask is filled with 1.6 mol of Bry, 1.7 mol of Oct, and 1.0 mol of BrCl. The following reaction becomes possible: Br2(8) +OC1,() - BrOCI(g) +BrCl(g) The equilibrium constant K for this reaction is 2.54 at the temperature of the flask. Calculate the equilibrium molarity of Brz. Round your answer to two decimal places. OM X 5 ?
Suppose a 250. mL flask is filled with 2.0 mol of OCl 2 , 1.4 mol of BrOCl and 1.5 mol of BrCl . The following reaction becomes possible: + Br 2 g OCl 2 g + BrOCl g BrCl g The equilibrium constant K for this reaction is 7.62 at the temperature of the flask. Calculate the equilibrium molarity of Br 2 . Round your answer to two decimal places.
Suppose a 250. mL flask is filled with 1.8 mol of No₃ and 1.5 mol of NO₂. The following reaction becomes possible: No₃(g) + No(g) ⇄ 2No₂(g) The equilibrium constant K for this reaction is 3.20 at the temperature of the flask. Calculate the equilibrium molarity of No₂. Round your answer to two decimal places.
Suppose a 250. mL flask is filled with 0.50 mol of H20, 1.0 mol of Co2 and 1.5 mol of H2. The following reaction becomes possible cog)+H20(g)Co()+H28) The equilibrium constant K for this reaction is 4.10 at the temperature of the flask Calculate the equilibrium molarity of H20. Round your answer to two decimal places.
Suppose a 250 ml flask is filled with 1.0 mol of NO and 0.70 mol of NO . The following reaction becomes possible: NO3(8) + NO(g) - 2NO(8) The equilibrium constant K for this reaction is 5.78 at the temperature of the flask. Calculate the equilibrium molarity of NO3. Round your answer to two decimal places. Ом 3 ? Expiat tion Check 20:30 MCGHE AB
Suppose a 250. ml flask is filled with 1.5 mol of Cl, and 1.3 mol of HCl. The following reaction becomes possible: H2(g) + Cl2(g) 2HCl (8) The equilibrium constant K for this reaction is 0.560 at the temperature of the flask. Calculate the equilibrium molarity of H. Round your answer to two decimal places. OM * 5 ?
Suppose a 250. ml flask is filled with 1.8 mol of OC1, 0.70 mol of BroCl and 0.50 mol of BrCl. The following reaction becomes possible: Br2(g) + OC12(g) – Brocl(g) +BrCl(g) The equilibrium constant K for this reaction is 1.48 at the temperature of the flask. Calculate the equilibrium molarity of BroCl. Round your answer to two decimal places. x 5 ?