Question

12 poists SEssCalkET1 7.2038 The base of S is a circular disk with radius 4r. Parallel cross-sections perpendicular to the base are isosceles triangles with height 3h and unequal side in the base. (a) Set up an integral for the volume of S V16r-dz 6h S V16r dr 6h 6h rdr O (162-)d 6h V16 de (b) By interpreting the integral as an area, find the voluame Vof S Noed Help? Read to ak to a Tutor

Answer 1

Area of usoucclo A = 1X bau Xhughd 2 cach crosschon of Arta yr -1x 3hХ Ь aae 2 Now volume is formid by hraing dlong CroJ rechons Vowm of crausahon with widthdr Oc dirtchon Ло 1xзh хь as X doc Now bas io uqualtougmnt= ndad yx for ht and 2nd quacrand y V16r2 2. Now 9/=Ct Vouum of crossscchon width dr 2 2 орX *191AxхчЕХТ 7оp -191 чЕ Чr So ntal volum 3h V16r2 do -Чr Чr вy ymming 2/3h VIr da =16h j16 ,7^_x*da 2 da 2

)+ ax* +c aSin : Voliume -Gh|16rsin'(s 2 |hurc a= 4r 16r2in - 6h 16r sin(r 2 Yr Чr LX 119X9 12Чhr