Tom and Jerry both push on the 3.00 m --diameter merry-go-round shown in (Figure 1) ....
Tom and Jerry both push on the 3.00 m --diameter merry-go-round shown in (Figure 1) . Tom pushes with a force of 47.5 N and Jerry pushes with a force of 35.5 N .
60o tom, 80o jerry
What is the magnitude of the torque exerted by Tom?
What is the magnitude of the torque exerted by Jerry?
Homework Answers
1) The radius is R = d/2 = 3.0/2 = 1.5m.
apply thr formula for torque T = r x F or r F sin theta
The torque by Tom is Ttom = F_t*R*sin60
Ttom = 47.5 *1.5*sin60 = 61.70 N-m.
The torque by Jerry is Tjerry = Fj*R*sin80
Tj = 35.5*1.5*sin80
Tj = 52.44 N-m
.The net torque is T = T1-T2
T = 61.7 - 52.44
T = 9.26 N*m. and it goes clockwise
-----------------------------------------
2) The net torque is T = T1 + T2
Tnet = 61.7 + 52.44
Tnet = 114.14 Nm and it goes counterclockwise
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