Question

Isotherms Adiabatic process T. Figure 1 5. Given is the P-V diagram, a gas system from state is undergoing a thermodynamic process which lead to a different state f. Assume the gas is monoatomic and following the ideal gas condition ) Show that the, area under i-flineP 1-7 i) If the system contains 5 mol of this gas with an initially temperature of 293 1 m3 to Vi K. Calculate the work done by the system expanding from V -4m3 ) the change of internal energy AU of the gas system.

Answer 1

< 1 > adiabatic process rightarrow p v^y = c area under I = F Line would be work done in adiabatic process w = integral p d u p v^y = c - p = c/v^y w =^v f_v i integral c/v^y d u w = c [v_f^1 - y - v_i^1 - y]/1 - y By equation p_i v_I^y = p_f v_f^y = c (p_i v_i) v_i^y - 1 = (p_f v_f) (v_f^y - 1) = c c v_1^1 - y = p_i v_I c v_f^1 - y = p_f v_f w = p_F v_f - p_I v I/1 - y n = 5 mol T_i = 293 k v_i = 1 m^3 v_f = 4 m^3 \r\n work done = ? p v = n R T v_1 = 1 m^3 = 1000 liter p_i times 1000 = 5 times 0.0821 times 293 p_i = 0.120 a