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Problem 4 An objects position function is given by x1(t) = 5 + 10t (with 2.1 in meters if t is in seconds). A second objects position function is 2(t) 5-6t. (a) If the first objects mass is 1/3 the mass of the second one, what is the position of the systems center of mass as a function of time? (b) Under the same assumption, what is the velocity of the systems center of mass?

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postion fucntion=X,(t)-5+10t and x, (t)-5-6t mlx1 + m2x2_m1(5+10) + 3m1(5-60- of mass -xc()mlxl+ m2x2_ ml(S+100) ml+ m2 ml+3ml b) velocity of m -v, -10 velocity of m-v, UX -dx2(t) dt mlvl+ m2v2 10ml-18ml velocity of centre of mass- m-一 ml+m2 4m l

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