How many ways are there to seat 8 people, consisting of 4 couples, in a row...

Question

Question

How many ways are there to seat 8 people, consisting of 4 couples, in a row of seats (8 seats wide) if all couples are to get adjacent seats?

math Statistics-And-Probability

Answer 1

Answer #1

4 couples can sit in 4! = 4 * 3 * 2 * 1 = 24 ways.

Now in each couple 2 people can sit in 2! = 2 * 1 = 2 ways.

So total number of ways = 24 * 2 = 48 (Ans)

** If the answer does not match please comment.

Answer 2

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