Question

7. How many grams of nitrogen (N) are there in a fertilizer containing 48.5 g of ammonium nitrate (NH4NO3) and no other nitrogen containing compound? 

Answer 1

We are anmenaa ma mitate Molasu ammenin niterate is mass mee mitaate 80 O43 Lmele wdaich meons centains 80 043 ammenac है b caludate the nuaben We meles Can ५ह .९. Moles Mass Molar Mass च र ह 8০.০4 meles No. ५৪.) O. 606 meles Imele حمنعممعععص ومميگ Now avgadrosmuaaleso 022 xo23)parntrickes JO ceutains mele 6.022x 1023 melacaules .606 eles will contai 3.65 X103 molecules. O606 x6.022 x 1023

১ Lmelecul centaims NHYNO, tnge(nyates 3-63 X10 23 melecules NHuo ioe 7.3 X Lo23 atevs Centain 2x 3.65 x1023 As mole atem 6.022 X o can naite We as Imole 6.022 X j0 atems meles Latom 6.022 x 1o23 X1023 atoms moles 6.022X102 3 73x LOs meles 6.022 x oz3 1-2 maees 7.-3X10 atems us re meles equiscalat Mo Ran Mass to .2 N గం eing NeLMoles f) x (oMlanrMass f Mass ि का) (० )

Thus 16.8 grams of nitrogen are contained in 48.5 g of ammonium nitrate.