Question

27. A ball is kicked with a velocity of 30m/s at an angle of 60 degrees relative to the horizontal. Assuming no air resistance ) What are the initial Vx and Vy components of the projectile shot? b) What will be the maximum vertical height the ball reaches in meters? c) How long in seconds will it stay in the air (hang time)? d) What will its velocity be at its maximum height? e) Calculate the total horizontal distance( range) of the ball

Answer 1

Velocity(v) = 30m/sec theta = 60 v_x = v cos theta = (30) cos 60 = 15m/sec v_y = v sin theta = (30) sin 60 = 25.98m/sec h_max = vy^2/2g = (25.98)^2/(2)(9.8) = 34.4m t = 2 v sin theta/g = (2)(25.98)/9.8 = 5.3sec at maximum height vertical component velocity is 0 and horizontal velocity v_x = 15m/sec therefore at maximum height v = v_x = 15m/sec horizontal distance (r) = v cos theta times t = (15) (5.3) = 79.5m