Question

12. A 20-turn circular coil (radius = 4.0 cm, total resistance = 0.20 2) is placed in a uniform magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies with time as given by B(t) = 50e-0.5t mt. where t is measured in seconds. What is the magnitude of the induced current in the coil at 3.0 s? (8 points) + 5 6. B r=.04m 3 why? 2000- R=.2002 B(E)=50est m N=20 (I. AN (HU) I.(MK60* (26)(2. to e -(-5)(50)-St 6(3:0) = -256-50) -25%mt

Answer 1

Induced euf (2)=-Ndo -- W d (BA) = -NA dB dt at - de Where w=wo. of turns 220 A = Area = 1T2 = 1 Cuidx102m² = 5.027x10 m2 -0.5t 0.5t = a (50 e de mi) = -0.5) (50) 20.st at -0. 5t =-25 X 103 ēst Ils R = Resistance =0.202 ;' L=-120115.027x10m)(-95 X1036-005771) = P.514x153 7 0.5t v at t=35, current I = { 2.514 X103 -0.5(35) - 0.202 1 = 2.80 x 10²A