Calculate enthalpy of combustion of acetone, C3H6O, given the following information:
(ΔH°f [ C3H6O(g)] = -285 kJ/mol
(ΔH°f [ CO2(g)] = -394 kJ/mol
(ΔH°f [ H2O(ℓ)] = -286 kJ/mol
Answer choices.....
A)-2613 kJ
B) -395 kJ
C) -1755 kJ
D) -585 kJ
E) -965 kJ
![C3H60(g) + 402 —> 3C02(g) + 3H2000) OH.com = [3*(-394-) + 3+(-286)] - [-285] =-1755 kJ](http://img.homeworklib.com/questions/90872570-3e48-11ea-8552-733b023712bc.png?x-oss-process=image/resize,w_560)
Calculate enthalpy of combustion of acetone, C3H6O, given the following information: (ΔH°f [ C3H6O(g)] = -285...
The enthalpy of combustion (ΔH°c) of 1,1,2,2,-tetramethylcyclopropane (C7H14) is -4635.62 kJ/mol. a-Using the appropriate information given below, calculate the enthalpy of formation (ΔH°f), in kJ/mol, for 1,1,2,2,-tetramethylcyclopropane. Report your answer to two decimal places. ΔH°f (CO2 (g)) = -393.51 kJ/mol ΔH°f (H2O (l)) = -285.83 b- Determine the mass (in g) of 1,1,2,2,-tetramethylcyclopropane produced, if ΔH° was determined to be -35.93 kJ during an experiment in which 1,1,2,2,-tetramethylcyclopropane was formed. Report your answer to three significant figures.
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The standard heat of formation, ΔH∘f, is defined as the enthalpy change for the formation of one mole of substance from its constituent elements in their standard states. Thus, elements in their standard states have ΔH∘f=0. Heat of formation values can be used to calculate the enthalpy change of any reaction. Consider, for example, the reaction 2NO(g)+O2(g)⇌2NO2(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) NO(g) 90.2 O2(g) 0 NO2(g) 33.2 Then the standard heat...
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