Question

Particles of charge +65, +48, and −95 μC are placed in a line (Figure 1) . The center one is L = 60 cm from each of the others.

Part A

Calculate the net force on the left charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Express your answer to two significant figures and include the appropriate units.

Part B

Calculate the net force on the center charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Part C

Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Answer 1

F_12 = k q_1 q_2 /R_12^2 = (9 times 10)^9(65 times 10^-6)(48 times 10^-6) /(0.6m)^2 Rightarrow -78 N F_13 = Kq_1 q_3/r_13^2 (9 times 10^9) (65 times 10^-6)(95 times 10^-6)/(1.2)^2 = 38.59 n F_net = F_12 + F_13 Rightarrow - 39.40 N B) F_12 = Kq_1q_2/r_12^2 = (9 times 10^9) (65 times 10^-6) (95 times 10^-6)/(0.6M)^2 rightarrow + 78 n F_13 = Kq_2q_3/r_23^2 = (9 times 10^9) (95 times 10^-6)(48 times 10^-6)/(0.6)^2 Rightarrow 7114N F_net = F_12 + F_13 Rightarrow 192N c) F_12 Kq_2q_3/r_23^2 = (9 times 10^9) (48 times 10^-6) (95 times 10^-6)/(0.6)^2 rightarrow -114N F_13 = Kq_1q_3/r_13^2 = (p times 10^9)(65 times 10^-6)(95 times 10^-6) (1.2_^2 rightarrow - 38.59 N F_net = F_12 + F_13 Rightarrow -152.59N