Question

A sample of CCl4 with a pressure of 1.23 atm and a volume of 240 mL is allowed to react with excess CH4 at 127 °C. CH4 (g) + CCl4 (g) --> 2 CH2Cl2 (g) Calculate the pressure of the CH2Cl2 produced in the reaction if it is transferred to a 2.77-L flask and cooled to 28 °C. _____atm

Answer 1

RT ® No. of moles of cold reacted (n) = RV P= . 23 alu - op n = 1.23x0.240 = 240 ml 0:082*400) = 0:240L = 0.009 moli R=0.08.2 L-atu IT=273+127) K Molok CHA(g) + cola (g) 2 CH2Cl2(g) S = 400K . 1 mol amol. After reaction no. of moles of CH2Cl269) produced = 2X0.009 moles, Now, the pressure of CH241269) = P = nRT I n = 2x0.009 or p = 2X0:009x0·082X301T={273+23)K 1 = 301 = 0.160 aitu V= 2:77 L ... The pressure = 0.160 aku Cans) 2.77