Question
moles of Mg reacted for Trial 1 and Trial 2. show calculations
Trial Trial 1 Measured Data 0.04 43,7 mL F4h mmHg Mass of Mg (g) (2pts) Volume of H2 gas (mL) (4pts) 44.3 ml Barometric Press
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Answer #1

Trial 1

Molar mass of Mg = 24.3 g/mol

Moles = mass /molar mass = 0.044 /24.3 = 0.0018 moles

Trial 2

Mass of Mg reacted = 0.04 gram

So moles of Mg reacted = 0.04/24.3 = 0.00164 moles

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