HomeworkLib
Question

The following data are from a completely randomized design. Treatment 163 145 123 142 157 121 166 129 132 144 145 144 148 138 153 191 138 131 159 142 134 344.8 88.8 152.8 Sample mean Sample variance a. Compute the sum of squares between treatments. Round the intermediate calculations to whole number. b. Compute the mean square between treatments. c. Compute the sum of squares due to error. d. Compute the mean square due to error (to 1 decimal).

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

The formula of sum of square between treatments is as follows:

SS_{b}=sum_{i=1}^{k}n_{i}*(ar X_{i}- ar {ar X})^{2}

Therefore,

X (1/3) * (1594 142+ 134) 145

SSb = 6*(159-145)^2 + 6*(142 - 145)^2 + 6*(134 - 145)^2 = 1176 + 54 +726 = 1956

Mean square between treatments = SSb / (k - 1) = 1956/(3-1) =1956/2 =978

d) Let's find mean square due to error

MSE =-* (s[+ s s )-* (344.84 88.84 152.8) = 195.4667

After rounding we get MSE = 195.5 ( this is the answer of part s

C) Sum of square due to error ( SSE)

SSE = ( n - k ) * MSE = ( 18 - 3) * 195.4667 = 2935 ( This is the answer of part c).

0 0
Add a comment
Know the answer?
Add Answer to:
The following data are from a completely randomized design. Treatment 163 145 123 142 157 121...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The following data are from a completely randomized design. Treatment 164 149 142 157 167 124...

    The following data are from a completely randomized design. Treatment 164 149 142 157 167 124 145 149 149 137 169 136 156 142 144 141.6 119.6 126 122 133 141 152 130 134 Sample mean Sample variance a. Compute the sum of squares between treatments. Round the intermediate calculations to whole number 1488 b. Compute the mean squ are between treatments. 744 c. Compute the sum of squares due to error. 135.33 d. Compute the mean square due to...

  • The following data are from a completely randomized design. Treatment 145 145 145 149134 151 140...

    The following data are from a completely randomized design. Treatment 145 145 145 149134 151 140 129 Sample mean Sample variance a. Compute the sum of squares between treatments. 159 310 142 108.8 134 145.2 b. Compute the mean square between treatments. c. Compute the sum of squares due to error d. Compute the mean square due to error (to 1 decimal), e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers....

  • The following data are from a completely randomized design. A 164, 142, 169, 145, 149, 167...

    The following data are from a completely randomized design. A 164, 142, 169, 145, 149, 167 Sample mean 156 Sample variance 144. B 147, 156,127, 147, 131, 144 Sample mean 142 Sample variance 119.2 C 124, 121, 134, 141, 158, 126, sample mean 134 sample variance 191.6. (1) Compute the sum of squares between treatments. (2) Compute the mean square between treatments. (3) Compute the sum of squares due to error. (4) Compute the mean square due to error (to...

  • e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest...

    e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers. Round all Mean Squares to one decimal places. Round F to two decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total f. At the α-.05 level of significance, test whether the means for the three treatments are equal The p-value is less than.01 What is your conclusion? Select The following data are from a...

  • The following data are from a completely randomized design. Treatment Treatment Treatment 32 30 30 26...

    The following data are from a completely randomized design. Treatment Treatment Treatment 32 30 30 26 32 30 35 38 37 38 42 38 6.5 45 45 47 49 46 Sample mean Sample variance At the α-.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error

  • The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32...

    The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 47 34 30 46 37 30 47 36 26 49 37 32 51 41 Sample mean 30 48 37 Sample variance 6 4 6.5 At the = .05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean...

  • Maintaining a healthy weight is important for women’s health. Some physicians recommend being back to your...

    Maintaining a healthy weight is important for women’s health. Some physicians recommend being back to your pre-pregnancy weight six months after giving birth. Public health officials are interested in whether this is a realistic goal. Do the women in North Carolina weigh more than their pre-pregnancy weight six months postpartum? In other words, is the six months post-pregnancy weight greater than their pre-pregnancy weight? Use a paired samples t-test to compare pst6wght (variable 1) and prewght (variable 2). This uses...

  • In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...

    In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). If the answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 1300 Error 700 Total 2000

  • Develop the analysis of variance computations for the following completely randomized design. At a = .05,...

    Develop the analysis of variance computations for the following completely randomized design. At a = .05, is there a significant difference between the treatment means? Treatment A В C 139 102 94 123 117 87 116 118 92 107 103 102 130 117 90 108 114 121 134 97 100 105 117 115 113 98 98 104 120.25 109.60 100.30 8174.21 73.38 117.57 Use the from the table to compute (to 2 decimals) Degrees Mean Square F (to 2 decimals)...

  • In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...

    In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). Round p-value to four decimal places. If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 1,300 --?-- --?-- ----?----- ---?------ ----?---- Error --?--      --?-- --?-- ----?----- ---?------ ----?---- Total 2,000     ...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT