Question

Part I Object A has two forces of magnitude 6 N each acting on it, as shown in the free-body diagram at right. ObjectA 45° 45° 6V 6N Object B has four forces of magnitude 3 N acting on it, as shown in the free- body diagram shown at right. Object B 45° 45 3N BN 3N 3N Question 1 Is the magnitude of the net force on object B greater than, less than, or equal to the magnitude of the net force on object A? The magnitude of the net force on object B is greater than the magnitude of the net force on object A. The magnitude of the net force on object B is less than the magnitude of the net force on object A The magnitude of the net force on object B is equal to the magnitude of the net force on object A. There is not enough information to answer this question Question 2 Explain the reasoning you used to answer the previous question.

Not sure how to answer this question.

Answer 1

For A, the horizontal component of both the forces are equal (6*cos(45)), and act in opposite directions

hence the net force is

F_A= 6*sin(45) + 6*sin(45) = 8.485 N

Similarly for B, the horizontal component of all the four forces cancel each other out

net force,F_B =  3*sin(45) + 3*sin(45) +  3*cos(22.5) + 3*sin(22.5) = 9.78 N