Question

The distribution coefficient of aspirin in ether / water at 25 ° C is 3.5. If 5.0g of aspirin is dissolved in 100 mL of ether:

a. How much aspirin can be extracted with 60.0 mL of water?

b. How much aspirin can be extracted with three successive portions of 20.0 mL each of water?

Answer 1

- Ether (loc moi). -water Neitz distribution low: At constant te rohelure a Solute dishibuze itself between two immiscible soivent only in a particular rolio. we have formula Here, Wo = Amount of solute left after exallion, W = Intial amount of solule CAspirin), Ķ Enistribution coefficient n = number of lot of extraction. Vi = volume of solule containing solvent (ether) V2 = volume of 200 solvent (water).

@ now, using equation .. hoe - [ en tres I 2x = 5.0 = 3.5 Vi = loomi tulisesti V2 = 6 miljoen ned.csingle lot of extraction). Het um - 3.5 X 100 3.5x100 +60] L person = [ 3.5*60060] photos 3.50 - . 350 356 5 350 +60 410 nahm = 350 x 5 hwn = 4.268 | Who wore in But, Amount of Aspirin extracted - fotol amount of Aspirin- Amount of a aspirin left

9mcum of Aspirin - 4 - 1 extracted - 1 = 5- 4.268 30.732.gi 0.732 g Aspirin can be extracted with of water. 6o mi now, Given that, w = 5. K = 3-5 Via Looml Hero V2 = 20 m. d n =3.63 lot uo fit for of exhaction.) rodo By using ean ®

out on a [ 164.00 j 3.5× Loo 3:5XL0o +20 um - 350 1350 120 350 370 l 2017 man - (per Pixs (350 310 / nain = 4.23 From ean D Amount of Aspirin extracted = 5 4 .23 = 0.77. :: 9.74_J Aspirin can be extracted with a successive partion of zomi to each of water.