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8) A given reaction absorbs 125 kJ of energy and gains 11.8 J/K of entropy. Under what conditions will the reaction be sponta

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Answer #1

\DeltaG =  \DeltaH -  T\DeltaS

amount of energy is absorbed = 125 KJ

hence , \DeltaH = +125 KJ

gains entropy, hence \DeltaS also positive

\DeltaS= + 11.8 J/K

reaction will be spontaneous when \DeltaG < 0

so,

T\DeltaS > \DeltaH

or, T > \frac{\Delta H}{\Delta S}

or, T > 125 x 1000 11.8

or,T > 10593 K .

hence reaction will be spontaneous above temperature 10593 K.

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