A 16-gram bullet moving at 1825 m/s plunges into 2.5 kg of paraffin wax. The wax was initially at 30°C. Assuming that all the bullet's energy heats the wax, what is its final temperature (in ºC)? Take the mechanical equivalent of heat to be 4 J/cal and the specific heat of wax to be 0.7 cal/g °C. Round your answer to the nearest 2 decimal places.
Concept: here kinetic energy of the bullet will be equal to the
heat energy needed to raise the temperature of the wax
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A 16-gram bullet moving at 1825 m/s plunges into 2.5 kg of paraffin wax. The wax...
Q12) A 19-gram bullet moving at 1689 m/s plunges into 2 kg of paraffin wax. The wax was initially at 25°C. Assuming that all the bullet's energy heats the wax, what is its final temperature (in ºC)? Take the mechanical equivalent of heat to be 4 J/cal and the specific heat of wax to be 0.7 cal/g °C.
A 5.00-g lead bullet moving at 400 m/s penetrates a wood block and comes to rest inside the block. If half of its kinetic energy goes into heating the bullet, what is the bullet's change in temperature? The specific heat of lead is 128 J/ (kg*K).
Lend has a specific heat of 128 J/kg°C. A lead bullet is moving at 650 m/s. If the bullet is suddenly stopped so that all of its kinetic energy is converted into heat, determine the temperature that the lead bullet reached before it was stopped. Take the initial temperature of the bullet to be 30 °C.
A 3.00 g bullet moving at 115 m/s strikes a 50.0 g stationary wooden block and embeds itself in the block. The bullet is made of lead, and the specific heat of lead is 128 J/(kg · °C). Assume the thermal energy generated in the collision is equally distributed in the bullet and the block. (a) Calculate the rise of temperature (T) of the bullet if block is clamped in place so that it cannot move. (b) Calculate the rise...
A 3.00 g bullet moving at 115 m/s strikes a 50.0 g stationary wooden block and embeds itself in the block. The bullet is made of lead, and the specific heat of lead is 128 J/(kg · °C). Assume the thermal energy generated in the collision is equally distributed in the bullet and the block. (a) Calculate the rise of temperature (DeltaT) of the bullet if block is clamped in place so that it cannot move. (b) Calculate the rise...
A 4.00-g lead bullet is traveling at a speed of 200 m/s when it embeds in a wood post. If we assume that half of the resultant heat energy generated remains with the bullet, what is the increase in temperature of the embedded bullet? (specific heat of lead = 0.0305 kcal/kg⋅°C, 1 kcal = 4 186 J)
given the information
answer
Common constants: 9.81 m/s2 = gravity on Earth's surface 343 m/s = speed of sound (air @ 20°C) 1440 m/s = speed of sound (water @ 20°C) 1.21 kg/mp = air density (20°C, 1 atm) 998 kg/m3 = water density (20°C, 1 atm) 1 atm = 1.01 x 105 Pa 3 x 108 m/s = c = speed of light (vacuum) 1.661x10-27 kg = p = atomic mass unit Specific Heats: 2040 J/(kg °C) Cwater =...
1) A 3.00 g bullet traveling horizontally at 400 m/s hits a 3.00 kg wooden block which is initially at rest on a smooth horizontal table. The bullet buries itself in the block without passing through. The speed of the block after the collision is a) 0.4 m/s. b) 1.2 m/s. c) 2.0 m/s. d) 2.8 m/s. e) 3.6 m/s. 2) What type of collision was seen in the previous problem? a) elastic collision b) inelastic collision c) perfectly elastic...
1) the kinetic energy of a 15.2 kg object traveling at 8.49 m/s is ___ J. 2) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. The specific heat of the substance is ___ J/g oC. 3) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. According to table 5.1 in the text, the sample may...
13. A 0.200-kg aluminum plate, initially at 20°C, slides down a 13.0-m-lon to the horizontal. The force of kinetic friction exactly balances the component of gravity down the plane so that the plate once started, glides down at constant velocity. If 90% of the mechanical energy of the system is absorbed by the aluminum is 900 J/kg)°C) g surface, inclined at a 25.0° angle aluminum, what is its temperature increase at the bottom of the incline? (Specific heat for a....