A baseball player hits a ball so that it leaves the bat at a speed of 45 m/s at 60 degree above the horizontal and at a height of 2 meters above the ground. Find its position at t=3s.
horizontal position
Dx = (v cos x) t
Dx = 45 cos 60 * 3 = 67.5 m
Vertical position
Dy = ho + (v sin x) t - 0.5*gt^2
Dy = 2 + 45 sin 60 * 3 - 0.5* 9.8* 3^2
Dy = 74.81 m
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A baseball player hits a ball so that it leaves the bat at a speed of...
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