A 30 nC charge experiences a 0.044 N electric force.
Homework Answers
Relation Between Electric field and electric force is given by:
F = |q|*|E|
|E| = Magnitude of electric field = F/|q|
Given that
F = 0.044 N
|q| = 30 nC = 30*10^-9 C
So,
|E| = F/|q|
|E| = 0.044/(30*10^-9)
|E| = 1466666.67 N/C
In two significant figures
|E| = 1.5*106 N/C = 1.5 MN/C
Where 1*106 = 1 M
Use Correct units in your final answer (N/C)
dear, u can refer the answer https://wizedu.com/questions/465/a-30-nc-charge-experiences-a-0035-n-electric-force
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