Question

The two forces F1 and F2 shown in figure 1 act on a 23.0kg object on a frictionless tabletop. Suppose that F1 = 12.0 N and F2 = 18.8 N.

Determine the magnitude of the net force on the object for the diagram (a) in the figure.

Answer 1

Answer 2

Answer 3

Net Force on object will be

Fnet = F1 + F2

F1 = 12 N in -ve x-axis = -12 i

F2 = 18.8 N in -ve y-axis = -18.8 j

So,

Fnet = -12 i - 18.8 j

Now magnitude of net force will be

|Fnet| = sqrt ((-12)^2 + (-18.8)^2)

|Fnet| = 22.3 N

Direction of Net force will be

direction = arctan ((-18.8)/(-12)) = 57.4 deg below -ve x-axis

direction = 180 + 57.4

Direction = 237.4 deg Counterclockwise from +ve x-axis

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