Question

Problem 1: block (m-7.0kg) is released from point A and it slides down the incline ( 0-40°) where the coefficient of kinetic friction is 0.25. It goes 5.0 m and hits a spring with a spring constant k=500 N/m. During the compression and the reaction of the spring, we assume that the bloc is moving on a frictionless surface (i = 0). a. How far is the spring compressed? b. What would be the velocity of the bloc when it is exactly at the middle ( 2.5 meters) upward ? -- frictionless

Answer 1

Guiven bock mass = 7KG- 0=400 Coefficient Kinetic frichomuc 0.25 Spring constant (6= 500 M det d' be the compressed distance wank done by forichon = Loss om polential energy - JAK* my como X Sm - Mik x mg *conce xd = mg *15-d) Sino +0.25 x 9.81 x COMI0) 5 +0.25x9.81 x COA-0) xd - 9.81x15-d) x Sın 40 (5+d) = (5-0)x 3.356 d = (5x3.3567 -5 = 2.7043 m (1+3-356) d = 27043 m. b wark dane by frichan = Spring poden hal energy. -Gravitahamal Potential energy -) - HK xmg x COSOVS = * 2-mg x (5+) Smo -) -0.25 X 7x9.8 X COA 40 X5 = 1X500X72-7x9.8 x (5+) Sin 40 - 65.688 = 250 -(44.695)(5+r) 250 4244695% - 44.695x5 + 65.688 = 0 250x2 - 44.095 - 154.788 = O * =/ +4.4.095 + (47.095?+ 4 X 250x 154.788 500 21=0.87997 m

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